Load the following direct command JK flip-flop schematic in the d-DcS, with a click on the figure:

Using the timing simulation , verify the behavior of the network. Pay attention to the two initialization inputs !Preset and !Clear. You should include all the possible combinations of the inputs J and K, after the activation of the inputs !Preset or !Clear (a suitable test sequence is available in the Timing Diagram window). Consider the particular case when J and K are active at the same time.

What happens if you don't initialize the network? Why, without the initialization, the simulator cannot solve the network configuration?